Solar Heating
You must
do this lab on a clear day. (DUH!) You
will be measuring the output of the Sun at the surface
of the Earth. This
will be in units
of power per unit area, or Watts per square meter (W/m2).
The apparatus will be shown to you in your lab section.
- Using the apparatus, heat 50 grams of water for 5 minutes. Measure
the temperature in degrees centigrade before and after to get the
temperature gain: before __________, after___________,
change______________. For best results, do this step two or
three
times, and average your measured change in temperature.
- Calculate the solar power required to do
this in Watts, as follows:
- Convert the temperature gain to calories. To do
this, remember that when you heat one gram of water one degree
centigrade, you have used one calorie of energy. You are
using 50 grams of water in this experiment so you need 50 times as much
energy for every degree of temperature increase. Water
heating: _________ cal.
- Convert calories to Joules, the metric unit of energy
(4.19 Joules equals 1 calorie): _________ J. (Check this!
Which number should be bigger, the number of Joules or the number of
calories?)
- One Joule/second (J/s) is one Watt (W).
So divide your energy in Joules by the number of
seconds of solar heating in your experiment. Solar power
collected: _________ W.
- Measure and calculate the area of the mirror in
square meters.
- Diameter in cm: _________ cm.
- Diameter in meters: _________ m.
- Radius in meters: _________ m.
- Area of circle = πr2 : _________
m2 (your web browser should
display the formula as pi times radius squared).
- Since you didn't collect all
the solar power the Sun produces, you should express just the part you
collected. This is done by quoting power (Watts) per
square meter, so that you only talk about the sunlight that
was collected by the mirror. Solar power sampled: ___________
W/m2.
- We now have a problem that always arises
when trying to collect energy, namely losses. The energy from the Sun
has passed through the glass of the mirror twice, and once through the
glass in the collector. Each
pass costs you something, because the glass isn't perfectly transparent
and the mirror isn't perfectly reflective (some energy is wasted
because the glass and mirror also heat up).
To
estimate how much solar energy REMAINS, you should write the fraction
of energy remaining for each step. In other words, if you
think
the mirror reflects 20% of the light (the real answer is much greater),
you would write 0.2 as the fraction remaining.
- fraction of light getting through the
atmosphere ___________
- fraction of light passing through mirror
glass ____________
- fraction of light reflected by mirror
______________
- fraction of light getting through the
hole _______________
- other losses (list them)
_________________
- etc.________________
- Net fraction of energy available to heat
water - multiply all fractions together ________________
The accepted value for
this the solar energy falling onto the Earth above the atmosphere is
about 1350 W/m2.
Divide your measured value for the solar constant by net
fraction of energy available.___________________
Compare this number to your measured value. Please
comment on this (how bad were your losses? are they just due to the
glass and the mirror? is your answer reasonable? if
not, try to find the mistake).
- Calculate the
total energy produced by
the sun. To do this, we'll need to compare the size of your
solar
collector (from part 3(d) above) to the size of the region where every
possible ray of sunlight can land. Look up any necessary
numbers
in your astronomy textbook. We will do this two different
ways,
and compare the answers. The first way uses your measured
solar
constant:
- Imagine a giant sphere
surrounding the Sun with a radius equal to the Earth’s
distance from the Sun (what is this distance?). Then the
Earth's orbit traces out the "equator" on that imaginary sphere. Calculate the surface area of this
sphere, since all light the Sun produces must pass
through it, using the following formula: Surface Area of a
sphere = 4πr2
= _______________ m2.
- Multiply
this (very large) number by the Watts per square meter you measured
above to get the total power the Sun produces: ____________ W.
- Look
up the accepted energy output of the Sun and calculate your percent
error: ____________ % error.
The second method uses the size and
temperature of the Sun:
- Calculate the surface area of
the Sun. Recall the formula from
the previous step, but be sure to use a different radius this
time: Surface Area of a sphere = 4πr2
= _______________ m2.
- The
energy per unit area of a black body is given by σT4,
(s should
show up as a greek sigma and is the Stefan-Boltzmann constant.)
____________ W/m2.
- Multiply
these two numbers to get the total energy output from the sun:
_________________W.
- Compare
your answers using the first and the second methods. They
should be close.
- Describe in a sentence or two the purpose
of this experiment: